BJT and FET circuits: board exam questions with solutions
On the ECE exam under Electronics Engineering. Try each question before you open its solution, then practise with fresh numbers below: 3 computed question types on this topic.
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BJT current gain (β) · Common-emitter amplifier · Transistor as a switch · MOSFET low-side switch · BJT small-signal model (hybrid-π): the same circuits on a live bench, with meters you can move.
Questions
1. A BJT has β = 150. What is its common-base current gain α?
- 0.0067
- 1.0067
- 0.9850
- 0.9934
Show the answer and solution
Answer: D. 0.9934
α = β/(β + 1) = 150/151 = 0.9934.
2. A voltage-divider biased silicon NPN stage has VCC = 12 V, R1 = 47 kΩ, R2 = 10 kΩ, RC = 3.3 kΩ and RE = 1 kΩ. Assuming β is large (IC ≈ IE) and VBE = 0.7 V, what is VCE?
- 7.36 V
- 2.95 V
- 5.96 V
- 2.11 V
Show the answer and solution
Answer: C. 5.96 V
VB = 12 × 10/57 = 2.105 V, VE = 1.405 V, IE = 1.405 mA, VCE = 12 − 1.405 × (3.3 + 1) = 5.96 V.
3. A BJT is biased at IC = 2 mA. Taking VT = 25 mV, what is its transconductance gm?
- 8 mS
- 80 mS
- 0.8 mS
- 12.5 mS
Show the answer and solution
Answer: B. 80 mS
gm = IC/VT = 2 mA/25 mV = 0.080 S = 80 mS. (12.5 Ω is re, not gm.)
4. A common-emitter amplifier has IE = 1 mA, RC = 4.7 kΩ and a fully bypassed emitter resistor. With VT = 25 mV and no load, what is the voltage gain?
- −188
- −4.7
- −4.7 × 10³
- +188
Show the answer and solution
Answer: A. −188
re = 25 mV/1 mA = 25 Ω; Av = −RC/re = −4700/25 = −188 (inverted output).
5. An n-channel JFET has IDSS = 10 mA and VGS(off) = −4 V. What is the drain current at VGS = −2 V?
- 5.0 mA
- 7.5 mA
- 0.0 mA
- 2.5 mA
Show the answer and solution
Answer: D. 2.5 mA
Shockley: ID = IDSS(1 − VGS/VGS(off))² = 10(1 − 0.5)² = 2.5 mA.
6. When does an n-channel enhancement-mode MOSFET begin to conduct significant drain current?
- When VGS = 0 V
- When VGS is made negative
- When VGS exceeds the threshold voltage VGS(th)
- When VDS exceeds the gate voltage, regardless of VGS
Show the answer and solution
Answer: C. When VGS exceeds the threshold voltage VGS(th)
An enhancement MOSFET has no channel at VGS = 0; a positive gate voltage above VGS(th) induces the n-channel.
7. An n-channel enhancement MOSFET in saturation follows ID = k(VGS − Vt)² with k = 0.5 mA/V² and Vt = 1 V. At VGS = 3 V, what is gm?
- 1.0 mS
- 2.0 mS
- 4.0 mS
- 0.5 mS
Show the answer and solution
Answer: B. 2.0 mS
ID = 0.5(3 − 1)² = 2 mA; gm = dID/dVGS = 2k(VGS − Vt) = 2 × 0.5 × 2 = 2.0 mS.
8. Which BJT configuration has a voltage gain of about one, high input impedance and low output impedance?
- Common collector (emitter follower)
- Common emitter
- Common base
- Cascode
Show the answer and solution
Answer: A. Common collector (emitter follower)
The emitter follower's output tracks the input minus VBE, so Av ≈ 1; its input impedance is about β(re + RE) and output impedance is low, making it a buffer.
Worked examples with computed numbers
These numbers are fixed on this page; in practice they change every time.
9. A voltage-divider-biased NPN amplifier has VCC = 20 V, R1 = 33 kΩ, R2 = 6.8 kΩ and RE = 1.2 kΩ. With VBE = 0.7 V and β large, what is the collector current?
- 2.26 mA
- 1.13 mA
- 2.85 mA
- 564 µA
Show the answer and solution
Answer: A. 2.26 mA
Stiff divider: VB = 20 × 6.8k/39.8k = 3.42 V; VE = VB − 0.7 = 2.72 V; IC ≈ IE = VE/RE = 2.26 mA.
10. A BJT with β = 150 has a base current of 25 µA. What is the emitter current?
- 25 µA
- 24.8 µA
- 3.75 mA
- 3.78 mA
Show the answer and solution
Answer: D. 3.78 mA
IE = IB + IC = (β + 1)IB = 151 × 25 µA = 3.78 mA.
11. An enhancement NMOS with k = 2 mA/V² (ID = ½k(VGS − VT)²) and VT = 2 V is in saturation with VGS = 3 V. What is ID?
- 2 mA
- 1.5 mA
- 9 mA
- 1 mA
Show the answer and solution
Answer: D. 1 mA
In saturation ID = ½k(VGS − VT)² = ½ × 2 mA/V² × (3 − 2)² = 1 mA.
Other topics in the same subjects
DC circuits · AC circuits · Transients (RC, RL, RLC) · Semiconductors and diodes · Operational amplifiers · Oscillators and feedback · Power electronics · Digital electronics · Microprocessors and microcontrollers · Control systems · Instrumentation and measurement
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