Integral calculus: board exam questions with solutions
On the ECE exam under Mathematics and the REE exam under Mathematics. Try each question before you open its solution, then practise with fresh numbers below: 2 computed question types on this topic.
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Questions
1. Evaluate the integral of 3x² dx from x = 0 to x = 2.
- 8
- 12
- 6
- 24
Show the answer and solution
Answer: A. 8
The antiderivative is x³, and 2³ − 0 = 8.
2. Find ∫ cos x dx.
- −sin x + C
- cos x + C
- −cos x + C
- sin x + C
Show the answer and solution
Answer: D. sin x + C
d/dx (sin x) = cos x, so ∫ cos x dx = sin x + C.
3. Find the area enclosed between y = x and y = x² from x = 0 to x = 1.
- 1/2
- 1/6
- 1/3
- 5/6
Show the answer and solution
Answer: B. 1/6
For 0 ≤ x ≤ 1, x ≥ x², so A = ∫(x − x²)dx = 1/2 − 1/3 = 1/6.
4. Evaluate the integral of sin x dx from 0 to π.
- 2
- 0
- 1
- −2
Show the answer and solution
Answer: A. 2
[−cos x] from 0 to π = −cos π + cos 0 = 1 + 1 = 2.
5. Find ∫ x eˣ dx.
- eˣ(x + 1) + C
- x²eˣ/2 + C
- eˣ(x − 1) + C
- xeˣ + C
Show the answer and solution
Answer: C. eˣ(x − 1) + C
Integrate by parts with u = x and dv = eˣdx: xeˣ − ∫eˣdx = eˣ(x − 1) + C.
6. What is the average value of f(x) = x² on the interval [0, 3]?
- 9
- 4.5
- 1
- 3
Show the answer and solution
Answer: D. 3
Average = (1/3)∫₀³ x² dx = (1/3)(27/3) = (1/3)(9) = 3.
7. The region under y = √x from x = 0 to x = 4 is revolved about the x-axis. Find the volume of the solid generated.
- 8.00 cubic units
- 50.27 cubic units
- 25.13 cubic units
- 16.76 cubic units
Show the answer and solution
Answer: C. 25.13 cubic units
By the disk method, V = π∫₀⁴ (√x)² dx = π∫₀⁴ x dx = π(16/2) = 8π = 25.13 cubic units.
8. Using the integral definition of RMS, V_rms = √[(1/T)∫v² dt], find the RMS value of v = 100 sin ωt V.
- 63.66 V
- 70.71 V
- 50.00 V
- 100.00 V
Show the answer and solution
Answer: B. 70.71 V
(1/T)∫(100 sin ωt)² dt = 100²/2 = 5000, so V_rms = √5000 = 70.71 V. 63.66 V is the average over a half cycle.
Worked examples with computed numbers
These numbers are fixed on this page; in practice they change every time.
9. Evaluate ∫ from 2 to 6 of (4x² − 2x) dx.
- 258.7
- 252
- 120
- 245.3
Show the answer and solution
Answer: D. 245.3
∫(4x² − 2x)dx = 4x³/3 − 2x²/2; from 2 to 6: 245.3.
10. Find the area bounded by y = x² and y = 9x.
- 121.5
- 40.5
- 364.5
- 243
Show the answer and solution
Answer: A. 121.5
They meet at x = 0 and x = 9. A = ∫₀^9 (9x − x²)dx = 9³/2 − 9³/3 = 9³/6 = 121.5.
Other topics in the same subjects
Algebra · Trigonometry · Analytic geometry · Differential calculus · Differential equations · Complex numbers · Probability and statistics · Matrices and determinants · Laplace transforms and Fourier series
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