Series-parallel network
Reduce the network step by step: combine the parallel pair first, then add the series parts. Work back out to find each branch current.

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How it works
R2 ∥ R3 = 1.32 kΩ
Req = R1 + (R2 ∥ R3) + R4 = 2.79 kΩ
I = 3.226 mA. Vpar = I · (R2 ∥ R3) = 4.258 V. The pair then splits I by I2 = Vpar/R2 and I3 = Vpar/R3.
Try it on the bench
- Change R3 and predict the new V_par before you look.
- Short R4 out with a wire. The pair now gets a bigger share.
Parts on the bench
- Bench power supply
- 2 × Digital multimeter
- 4 × Resistor
In the course
Zen’s Electronics Design Mastery, module “DC Fundamentals”.