Norton equivalent
The same network can also be replaced by a current source I_N in parallel with R_N. I_N is the short-circuit current, and R_N equals R_th.

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How it works
IN = current through a short across a–b = Vth / Rth = 7.127 mA
RN = Rth = 1.16 kΩ
A load in parallel takes VL = IN · (RN ∥ RL).
Try it on the bench
- Click the changeover switch S to put the load on the original network. V_L then matches V_L’.
- Thévenin and Norton are the same thing: V_th = I_N · R_N.
Parts on the bench
- Bench power supply
- 5 × Resistor
- Changeover switch
- 3 × Digital multimeter
- Current source
- Potentiometer
In the course
Zen’s Electronics Design Mastery, module “DC Circuit Analysis”.