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Phone charging: volts, amps and watts

USB and power interfaces · Beginner · about 15 minutes · part of Zen’s Electronics Design Mastery

A phone shows the volts and amps it measures at its own USB port. A DC watt meter on the 12 V side shows what goes in. The difference is lost in the 12 V → 5 V converter and in the USB cable: watts in = watts out + losses.

Phone charging: volts, amps and watts: the circuit on the simulator's bench

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How it works

Watt meter (12 V side): P = V × I = 0 V × 0 A = 0 W

Phone screen (5 V side, after the cable): 0 V × 0 A = 0 W

Converter + cable efficiency = 0 W ÷ 0 W = —. Into the battery: about 0 W, so the phone itself loses another 0 W as heat.

The phone takes 2 A at most from a wall-charger port, so it shows 2 A × the voltage left after the cable: 0 W, not the 10 W printed on a “5 V 2 A” label. The current on the 12 V side is lower than on the 5 V side, because the power is the same and the voltage is higher.

Try it on the bench

  1. Select the USB cable and change it to 28 AWG, 2 m: the phone sees VBUS sag, its AICL cuts the current and the screen shows fewer watts.
  2. Delete the HW-688 and plug the phone into a USB-C PD charger with a C → C cable: it fast-charges at 9 V and about 18 W.
  3. Click the watt meter screen to see Wh and the peak current. Click RST to zero it.
  4. Set the phone’s battery to 85 %: charging moves to constant voltage and the current tapers off.

Parts on the bench

In the course

Zen’s Electronics Design Mastery, module “Capstone — Connected Tracker”.

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